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## How many 5 digit numbers can be formed using 0 9 with repetition?

Since every **number can** be repeated on any place so in each of the **digit’s** place there are totally 10 possible **numbers** i.e. 0 to 9. 10*10*10*10*10 = 10^ **5**.

## How many 5 digit numbers can be formed using 1/9 if no digit can appear more than twice?

Overall, there are 25,200 **5 digit numbers with no digit** repeating **more than twice**. This is still only just about 1/4th of 90,000 possible **5 digit numbers**.

## How many number of 5 digits can be formed?

Repetition of **digits** is allowed. ∴ Each place out of unit, 10th, 100th and 1000th **can** be filled in **5** ways. Total **numbers** =4×**5**×**5**×**5**×**5**=2500.

## How many possible combinations are there for a 5 digit number?

Assuming the first digit can be 0, there are **100000** such combinations (because after chopping off the initial zeroes, each combination gives a number between 0 and **99999** and there are obviously **100000** of those).

## How many 10 digit number combinations are there?

If you have 10 digits then the maximum number possible is: **9,999,999,999**. Since the sequence starts at ** we need to add 1. So 10,000,000,000 (10 billion). That is how many numbers can be represented in 10 digits, it is not the number of phone numbers possible. **

## How many 6 digit combinations are there using 0-9?

**There** are 900000 **possible** ways to get **6 digit** numbers **using 0 – 9**.

## How many numbers are there in 5?

The largest 5 digit number is **99999**. **99999** minus **10000** is **89999,** but since you have a zero-based count, you have to add 1. That means there are a total of 90,**000** different 5 digit numbers. Hence, there are 90,**000** 5-digit numbers.

## How many 4 digit numbers can be formed in which all the digits are different?

There will be as **many 4**–**digit numbers** as there are permutations of 5 **different digits** taken **4** at a time. 5 5 **4** 5 1 P!!!! = 5 × **4** × 3 × 1 × 1 = 120 Among the **4**–**digit numbers formed** by using the **digits**, 1, 2, 3, **4**, 5, even **numbers** end with either 2 or **4**.

## How many numbers of 5 digits can be formed with the digits 0 2 3 4 and 5 if the digits may repeat?

{**, 2, 3, 4, 5} –> 96 5–digit numbers possible with this set. If 0 is not included: {1, 2, 3, 4, 5} –> 120 5–digit numbers possible with this set. {1, 2, 3, 4, 6} –> 120 5–digit numbers possible with this set. **

## How many five digit number can be made from the digits 1 to 7 if repetition is allowed?

How **many five**–**digit numbers can be made from the digits 1 to 7 if repetition is allowed**? Explanation: **7**^{5} = 16807 ways of making the **numbers** consisting of **five digits if repetition is allowed**.

## How many 5-digit numbers can be formed which are divisible by 3?

Therefore, we have a total of 120 + 96 = 216 ways to form a **five**–**digit number** that is **divisible by 3**.

## How do you calculate the number of possible combinations?

The formula for **combinations** is generally n! / (r! (n — r)!), where n is the total **number of possibilities** to start and r is the **number** of selections made.

## How many 6 digit are there in all?

∴ there are **900,000 6**-digit numbers in all.

## What are all the possible combinations of 1234?

What are all the possible combinations of 1234? If you wager on 1234 boxed, you would win if any of the following combinations were drawn: 1234, 1243, 1324, 1342, 1423, 1432, 2134, 2143, 2314, 2341, 2413, 2431, 3124, 3142, 3214, 3241, 3412, 3421, 4123, 4132, 4213, 4231, 4312, or **4321**.

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